Assalomu alaykum, yordam.uz saytimizga xush kelibsiz.
Bu saytda o`zingizni qiziqtirgan savollarga javob olishingiz va o`z sohangiz bo`yicha savollarga javob berishingiz mumkin. Bizning Oilamizga a'zo bo`lganingiz uchun chuqur Minnatdorchilik bildiramiz !!!

Jadvaldagi eng katta ko`paytma

+6 ovoz
128 marta ko‘rilgan
so‘radi 12 fevral, 17 Jahongir Soataliyev (260 bal)
tahrirlandi 12 fevral, 17 Jahongir Soataliyev

Quyidagicha jadval berilgan:

08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48

Shu jadvalda qizil rangda berilgan sonlarning kopaytmasi: 26 x 63 x 78 x 14 = 1788696;

Pastga va o'ngga hisoblaganda eng katta ko`paytmani hisoblang. 

masala shunday berilgan.

Men bunday tarzda yechdim:

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int[][] massiv = new int[20][20];
        int chek = 4;
        int natija = 1;
        for (int i = 0; i < 20; i++) {
            for (int j = 0; j < 20; j++) {
                massiv[i][j] = scanner.nextInt();
            }
        }
        /* bu yerda qator hisoblanadi */
        for (int i = 0; i < 20; i++) {
            for (int j = 0; j < 20 - chek; j++) {
                int kopaytma = massiv[i][j] * massiv[i][j + 1]
                        * massiv[i][j + 2] * massiv[i][j + 3];
                if (kopaytma > natija) {
                    natija = kopaytma;
                }
            }

        }
        /* bu yerda ustun hisoblanadi */
        for (int i = 0; i < 20; i++) {
            for (int j = 0; j < 20 - chek; j++) {
                int kopaytma = massiv[j][i] * massiv[j + 1][i]
                        * massiv[j + 2][i] * massiv[j + 3][i];
                if (kopaytma > natija) {
                    natija = kopaytma;
                }
            }
        }
        /* bu yerda diagonal hisoblanadi */
        for (int i = 0; i < 20 - chek; i++) {
            for (int j = 0; j < 20 - chek; j++) {
                int kopaytma = massiv[i][j] * massiv[i + 1][j + 1]
                        * massiv[i + 2][j + 2] * massiv[i + 3][j + 3];
                if (kopaytma > natija) {
                    natija = kopaytma;
                }
            }
        }
        System.out.println(natija);
    }

yechim esa 51267216 chiqdi.

Saytda buni xato berdi.

izoh qoldirdi 13 fevral, 17 Saidolim (3,566 bal)
Eng katta son deganda, faqat 4 ta bo`lishi kerakmi? yoki xohlagancha sonlarni ko`paytirish mumkinmi?  qo`shimcha shartlarini ham yozing.

1 ta javob

+2 ovoz
javob berdi 19 fevral, 17 FAXRIDDIN TOJIBOYEV (306 bal)
tahrirlandi 20 fevral, 17 FAXRIDDIN TOJIBOYEV
https://projecteuler.net/problem=11

Jahongir ba'zi shartlarini yozish sal esdan chiqibti

Man c++ da tuzishga harakat qib kordim

#include<iostream>
using namespace std;
int m(int a, int b){
    int x;
    x = (a > b) ? a : b;
    return x;
}

int main()
{
    const int n = 20;

int a[n][n], i, j, m1, m2, mm, p1, p2;
             for (i = 0; i < n; i++)
             for (j = 0; j < n; j++)
                 cin>>a[i][j];
             m1 = a[0][0] * a[1][1] * a[2][2] * a[3][3];
             m2 = a[3][0] * a[2][1] * a[1][2] * a[0][3];
             for (j = 0; j < n - 3; j++)
             for (i = 0; i < n - 3; i++){
                 p1 = a[i][j] * a[i + 1][j + 1] * a[i + 2][j + 2] * a[i + 3][j + 3];
                 m1 = m(p1, m1);//o'ng doagonal bo'yicha topadi
                 p2 = a[i + 3][j] * a[i + 2][j + 1] * a[i + 1][j + 2] * a[i][j + 3];
                 m2 = m(p2, m2);//chap doagonal bo'yicha topadi
             }
             m1 = a[0][0] * a[1][0] * a[2][0] * a[3][0];
             m2 = a[0][0] * a[0][1] * a[0][2] * a[0][3];
             for (i = 0; i< n; i++)
             for (j = 0; j< n - 3; j++){
                 p1 = a[j][i] * a[j + 1][i] * a[j + 2][i] * a[j + 3][i];
                 m1 = m(p1, m1);//vertikal bo'yicha topadi
                 p2 = a[i][j] * a[i][j + 1] * a[i][j + 2] * a[i][j + 3];
                 m2 = m(p2, m2);//gorizontal bo'yicha topadi
             }
             mm = m(m1, m2);
    cout << mm;
    return 0;}
izoh qoldirdi 19 fevral, 17 FAXRIDDIN TOJIBOYEV (306 bal)
Javob 70600674 chiqdi

Assalomu alaykum, yordam.uz saytimizga xush kelibsiz.

Bu saytda o`zingizni qiziqtirgan savollarga javob olishingiz va o`z sohangiz bo`yicha savollarga javob berishingiz mumkin.

Bizning Oilamizga a'zo bo`lganingiz uchun chuqur Minnatdorchilik bildiramiz !!!

Telegram kanal YordamUzRss

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